Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
= 5n
Step-by-step explanation:
There is a common difference d between consecutive terms
d = 10 - 5 = 15 - 10 = 20 - 15 = 25 - 20 = 30 - 25 = 5
This indicates the sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 5 and d = 5 , then
= 5 + 5(n - 1) = 5 + 5n - 5 = 5n
Answer:
use socratic
Step-by-step explanation: