Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?
2 answers:
Answer:
x² + y² = 34
Formula:
- (x - h)² + (y - k)² = r² where (h, k) is the center
<u>Here find the radius using distance formula</u>: → origin : (0, 0)
<u>Thus the equation of circle</u>:
- (x - 0)² + (y - 0)² = (√34)²
Answer:
H. 
Step-by-step explanation:
<u>Equation of a circle (in standard form)</u>
<u />
(where (h, k) is the center and r is the radius of the circle)
Given center = (0, 0):


As the circle passes through point (3, 5):


<u>Final equation</u>
<u />
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