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aliina [53]
3 years ago
8

Which is a solution of -3/5+3/8=

Mathematics
1 answer:
pshichka [43]3 years ago
7 0
This is your perfect answer

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Two candidates are randomly selected. a. List all the possible outcomes. b. What is the probability that both are qualified? c.
steposvetlana [31]

Question:

Four candidates are to be interviewed for a job. Two of them, numbered 1 and 2, are qualified, and the other two, numbered 3 and 4, are not.

Answer:

a. S = {12,13,14,23,24,34}

b. 1/6

c. ⅔

Step-by-step explanation:

Let S = Sample Space i.e. total possible outcomes

Given that candidates 1 and 2 are qualified and 3 and 4 are not qualified.

If two candidates are randomly selected. The list of all possible outcomes is as follows

S:{12,13,14,23,24,34}

And the number of outcomes is 6

b. What is the probability that both are qualified?

The event that both are qualified is given as {12} or {21}

From the sample space in (a) above, there's only one occurrence of {12} = 1

So, the probability is calculated as 1/6

c. What is the probability that exactly one is qualified?

The event that one one is qualified is given as {13,14,23,24}

Total = 4

Probability = 4/6

Probability = ⅔

5 0
3 years ago
What is 3 4/8 + 7 1/2
vivado [14]

Answer:

11

Step-by-step explanation:

3+7=10

4/8=1/2

12+1/2=1

10+1=11

6 0
3 years ago
Read 2 more answers
What is the range of the function y=2x+1 for the domain 2<=x<=5?
egoroff_w [7]
So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range

sub 2 for x
y=2(2)+1
y=4+1
y=5

sub 5 for x
y=2(5)+1
y=10+1
y=11

so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}
5 0
3 years ago
Help pls, i dont get the question
aksik [14]
[0,&) maybe it’s this
7 0
3 years ago
What is the approximate volume of the cone? ​
KonstantinChe [14]

Answer:

157 cm³

Step-by-step explanation:

Given

Radius (r) = 5 cm

height (h) = 6 cm

Volume of the cone (V) = ?

We have the formula

V = 1/3 *π*r²*h

V = 1/ 3 * 3.14 * 5² * 6

V = 157 cm³

Hope it will help :)

7 0
3 years ago
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