All categories

2 years ago

Santiago receives an allowance of $7 every week. how much total does he receive.

Mathematics

2 answers:

Gennadij [26K]2 years ago

8 0

Answer:

7 for each week

Step-by-step explanation:

7:1 = 7 dollars in 1 week

14:2

21:3

28:4

35:5

42:6

49:7

56:8

63:9

70:10

77:11

84:12

igor_vitrenko [27]2 years ago

5 0

Answer:

How many weeks 23 34 85? if its 23 161 if its 34 238 and if its 85 595

Step-by-step explanation:

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Neporo4naja [7]

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If M = 5x2 + 7x - 4 and N = -3x2 - 4x + 5, then M - N equals

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Answer

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Step-by-step explanation:

That is the answer :))

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const2013 [10]

Melanie walked 2.2 miles. Cathy walked 1.75 times as far. This means that you need to do 2.2 * 1.75 which equals 3.85. To find how much further, do 3.85 - 2.2 which equals 1.65. Therefore Cathy walked 1.65 more miles than Melanie.

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2 years ago

Write the number in standard notation. 4.16 × (10) ^–5

yaroslaw [1]

Answer:

.0000416

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago