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3 years ago

Solve the inequality. 4(x + 3) − 7 ≥ x + 3(x + 1)

Mathematics

1 answer:

weqwewe [10]3 years ago

5 0

Answer:

if want to know is true or flas. this is true

Step-by-step explanation:

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So when you are adding fractions how do you know when you need to simplify the numbers and how do you simplify?

rosijanka [135]

Let's look at an example.

We'll add the fractions 1/6 and 1/8

Before we can add, the denominators must be the same.

To get the denominators to be the same, we can...

multiply top and bottom of 1/6 by 8 to get 8/48
multiply top and bottom of 1/8 by 6 to get 6/48

At this point, both fractions involve the denominator 48. We can add the fractions like so

8/48 + 6/48 = (8+6)/48 = 14/48

Add the numerators while keeping the denominator the same the entire time.

The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.

14/2 = 7
48/2 = 24

The fraction 14/48 reduces to 7/24

Overall, 1/6 + 1/8 = 7/24

6 0

2 years ago

Economists predict that Americans will spend $1,180 on electonics in

lisov135 [29]

Money spent by Americans last year=$1,180-6.8% of $1,180
=$1099.76

8 0

2 years ago

theresa went bowling on tuesday night. she bowled scores of 150, 165, and 165. what was her mean average score?

aleksley [76]

So, to do this, all you need to do is add up all the values, and then, with that number, divide by how many values are given.

150+165+165= 480
480/3= 160

7 0

3 years ago

Read 2 more answers

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=2x%2B3%3D8%3Cbr%3E%0A" id="TexFormula1" title="2x+3=8&#10;" alt="2x+3=8&#10;" align="a

ruslelena [56]

$x\in \mathbb{R}$

6 0

3 years ago