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3 years ago

8

during a promotion bags of sweets contain 30% extra free. There are 65 sweets in a bag during the promotion. How many sweets are

there normally

1 answer:

earnstyle [38]3 years ago

4 0

Answer:

if y is the normal number of sweets then the normal number plus 40 percentage equals 42

y+4y=42

1.4y=42

y=42/1.4=30

hope this helps!

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A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe

PSYCHO15rus [73]

Answer:

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2 bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let A = (u - E) * ( $\sqrt{n}$ / s) be the test statistic

we want P( average_l < A < average_u ) = 95%

look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test

average_l = -1.96 which corresponds to the 2.5%

average_u = 1.96

P( -1.96 < A < 1.96) = 95%

P( -1.96 < (u - E) * ( $\sqrt{n}$ / s) < 1.96) = 95%

Solve for the true mean E ok

E < u + 1.96* (s / $\sqrt{n}$ )

from -1.96 < (u - E) * ( $\sqrt{n}$ / s)

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s / $\sqrt{n}$ ) < E

26,226.2 - 518.7197348105429466 < E

25,707.48026519 < E

lower bound is 25,707.48026519

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

7 0

3 years ago

PLEASE HELPP thank youuu

nydimaria [60]

Answer:

#3) 2/5×2= 4/5 full bucket per one hour.

3 0

3 years ago

Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh

zepelin [54]

Answer:

$\large \boxed{\text{11 km/h}}$

Step-by-step explanation:

1. The situation after 15 min:

(a) Distance travelled by simulated biker:

15 min =¼ h

$\text{Distance} = \dfrac{1}{4}\text{ h} \times \dfrac{\text{20 km}}{\text{1 h}} = \text{5 km}$

(b) Distance travelled by Julian

Julian is 2¼ km behind the biker. The distance he has travelled is (5 - 2¼) km

5 - 2¼ = 5 - ⁹/₄ = ²⁰/₄ - ⁹/₄ = ¹¹/₄ = 2¾

Julian has travelled 2¾ km in ¼ h.

2. Julian's average speed

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}} = \dfrac{2\frac{3}{4}\text{ km}}{\frac{1}{4}\text{ h}} =\dfrac{11}{4}\text{ km}\times \dfrac{4}{\text{1 h}} = \textbf{11 km/h}\\\\\text{Julian's average speed is $\large \boxed{\textbf{11 km/h}}$}$

7 0

3 years ago

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the point (2,3) is in the terminal side of an angle theta, in standard position. what are the values of sine, cosine, and tangen

suter [353]

(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13

sina=3/√13, cosa=2/√13, tana=3/2 Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13

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3 years ago

Neo mixes 600ml of black paint with white paint in order to get grey paint. He thinks the colour came out too dark, so he decrea

butalik [34]

Answer:

the black paint is of 200 ml

Step-by-step explanation:

first he wanted grey paint by mixing 600 ml of both colour so he reduced black paint by 7:12 ratio an we get difference of 3 with that ratio so dividing 600 by 3 and we get amount of blacl paint removed

4 0

3 years ago