Answer:
Well 0.5 is the same as 1/2 but I'll try to help.
Step-by-step explanation:
1/9+1/8 is 0.2361. That would honestly be closer to zero but the way that it is worded, it is closer to 1/2 because you are using fractions in the problem. If you were using decimals, I would use 0.5
First use the chain rule; take
. Then

By the power rule,

By the quotient rule,



So


We have an equation with parentheses. To make our lives easier, first get rid of the parentheses. We do this by using the distributive property.
It is used like this: a(b + c) = ab + ac.
Use the distributive property on the left-hand side.
3(x - 1) = 6
3x - 3 = 6
Now we have an equation that is easier.
The x variable is being multiplied by 3 and added to -3.
Reverse all of these operations with their inverse operation.
3x - 3 = 6
3x = 9 <--- I got rid of the -3 term by using the inverse of subtraction. Addition.
And I did the same for both sides to keep the equation true.
x = 3 <--- The inverse of multiplication is division.
So, I divided both sides by 3.
So, x is equal to 3.