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tekilochka [14]
3 years ago
9

On a scale drawing of a park, the length of a trail is 12 cm from the playground to the pond and 15 cm from the pond to the park

ing lot. If the actual length of the trail from the pond to the parking lot is 60 m, what is the actual length of the trail between the playground and the pond? (Represent/Solve)
a. Define and determine a variable to help solve the problem: (remember look at what the problem is asking)
b. What two things are being compared?
c. Set up a proportion equation using your answer to b (remember “like” units
should be in same place in the proportion)
d. Fill in numbers to your proportion equation using the information from the
problem
e. Use your proportion to solve the problem (remember cross product strategy)
Mathematics
1 answer:
Katen [24]3 years ago
8 0

Answer:

The answer is 48 m

Step-by-step explanation:

In this situation,

15 cm = 60 m  

which means 1 cm = 60/15 m = 4m

therefore,

length of the trail between the playground and the pond in scale drawing= 12 cm

since, 1 cm= 4 m

therefore, 12 cm = 12*4 m = 48 m

the actual length of the trail b/w playground and pond = 48m

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Answer:

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Step-by-step explanation:

  M = (x + y)/2     Multiply both sides by 2

2M = x + y           Subtract x from each side

  y = 2M - x

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10÷(2x) when x= -5/4
Vladimir [108]

Answer:

-4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Step-by-step explanation:

<u>Step 1: Define</u>

10 ÷ (2x)

x = -5/4

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    10 ÷ (2(-5/4))
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Simplify the following surds :<br><br> 1) 2√21 × √27 ÷ √343<br> 2) 7√5 × √125 ÷ 2√27
ludmilkaskok [199]

Answer:

1) \frac{18}{7}

2) \frac{175\sqrt{3}}{18}

Step-by-step explanation:

* Lets explain how to simplify a square root

1)

∵ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343}

∵ \sqrt{21}=\sqrt{3} × \sqrt{7}

∴ 2\sqrt{21} = 2\sqrt{3} × \sqrt{7}

∵ \sqrt{27} = \sqrt{3} × \sqrt{3} × \sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∴ \sqrt{27} = 3\sqrt{3}

∴ 2\sqrt{21} × \sqrt{27} =

  2\sqrt{3} × \sqrt{7} × 3\sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∵ 2 × 3 × 3 = 18

∴ 2\sqrt{21} × \sqrt{27} = 18\sqrt{7}

∵ \sqrt{343} = \sqrt{7} × \sqrt{7} × \sqrt{7}

∵ \sqrt{7} × \sqrt{7} = 7

∴ \sqrt{343} = 7\sqrt{7}

∵ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343} =

  18\sqrt{7} ÷ 7\sqrt{7}

∵ \sqrt{7} ÷ \sqrt{7} = 1

∴ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343} =

  \frac{18}{7}

2)

∵ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27}  

∵ \sqrt{125} = \sqrt{5} × \sqrt{5} × \sqrt{5}

∵ \sqrt{5} × \sqrt{5} = 5

∴ \sqrt{125} = 5\sqrt{5}

∴ 7\sqrt{5} × \sqrt{125} =

  7\sqrt{5} × 5\sqrt{5}

∵ \sqrt{5} × \sqrt{5} = 5

∴ 7\sqrt{5} × \sqrt{125} = 7 × 5 × 5 = 175

∵ 2\sqrt{27} = 2\sqrt{3} × \sqrt{3} × \sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∴ 2\sqrt{27} = 6\sqrt{3}

∴ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27} =

  175 ÷ 6\sqrt{3} = \frac{175}{6\sqrt{3}}

∵ \frac{175}{6\sqrt{3}} not in the simplest form because

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∴ Multiply up and down by \sqrt{3}

∴  \frac{175}{6\sqrt{3}} = \frac{175\sqrt{3}}{6\sqrt{3}*\sqrt{3}}

∴  \frac{175}{6\sqrt{3}} = \frac{175\sqrt{3}}{18}

∴ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27} =

  \frac{175\sqrt{3}}{18}

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3 years ago
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