Answer:
ΔT = 13.65° C
ΔQ = 13.7 J
Explanation:
First we will find the final temperature of air by using equation of state:
P₁V₁/T₁ = P₂V₂/T₂
For Isochoric Process, V₁ = V₂
Therefore,
P₁/T₁ = P₂/T₂
T₂ = P₂T₁/P₁
where,
T₂ = Final Temperature = ?
P₂ = Final Pressure = 1050 mb
P₁ = Initial Temperature = 1000 mb
T₁ = Initial Temperature = 0°C = 273 k
Therefore,
T₂ = (1050 mb)(273 K)/(1000 mb)
T₂ = 286.65 K
Change in Temperature = ΔT = T₂ - T₁
ΔT = 286.65 K - 273 K
<u>ΔT = 13.65° C</u>
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The first law of thermodynamics can be written as:
ΔQ = ΔU + W
where,
ΔQ = heat absorbed
ΔU = change in internal energy = mCΔT
W = Work Done = 0 (in case of isochoric process)
Therefore.
ΔQ = mCΔT
where,
m = mass of air = 1 g = 1 x 10⁻³ kg
C = specific heat of dry air = 1003.5 J/kg.°C
Therefore,
ΔQ = (1 x 10⁻³ kg)(1003.5 J/kg.°C)(13.65°C)
<u>ΔQ = 13.7 J</u>
Answer:
Weight needed to balance the bar is 
Explanation:
Given the weight of the bar is 
The length of the bar is 
The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of
from both ends.
Now applying momentum equation about balanced load we get, (see attachment)

If you define the ground as position zero and points above that to have positive altitudes, then the acceleration caused by gravity points in the negative direction. ... Gravity still acts in the downward direction. And the upward force from the floor is equal and opposite to your weight.
Answer:
A transformer is a passive electrical device that transfers electrical energy from one electrical circuit to another, or multiple circuits.
Explanation:
Hope it helps
Answer:
speed of molecule ∝ 1/mass of molecule.
Explanation:
The velocities of the molecules depend on their masses. That's because if the molecules are large in size, their velocity is slower. Therefore their velocity is quicker when their size is small, since the molecules can move faster.
Therefore , it can be written as
speed of molecule ∝ 1/mass of molecule.