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liubo4ka [24]
3 years ago
10

How much kinetic energy do you think a ball will have if it were dropped from a 2-m shelf

Physics
2 answers:
Levart [38]3 years ago
8 0

5 joules hope this helps

Gre4nikov [31]3 years ago
5 0

That depends on how much mass the ball has, and what planet it's on.

The kinetic energy it has when it hits the floor is the same as the potential energy it has when it's still on the shelf.  That's . . .

Potential energy = (mass of the ball) (gravity) (height off the floor)

Gravity on Earth is 9.8 m/s² .  

So if the shelf is on Earth, then the ball's kinetic energy when it hits the floor is . . .

Kinetic energy = (mass of the ball, in kg) (9.8 m/s²) (2 m)

<em>Kinetic energy = 19.6 · (mass of the ball, in kg)  Joules</em>

<em></em>

Up in the first answer, SWIMMY says it would have about 5 Joules.  That's the kinetic energy it would have IF the mass of the ball is 0.255 kilogram.  

Is that a reasonable mass for a ball ?  Well, an NFL football is 0.40-0.43 kilogram.  An NBA basketball is 0.62 kilogram.  Two major-league hardballs are 0.284-0.298 kilogram.  And 5 golf- balls are  0.229 kilogram.  So I guess 0.255 kilogram is not too unreasonable for a ball, and SWIMMY's estimate of 5 Joules of kinetic energy isn't bad ... after a fall from 2 meters.

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In boxing, the use of 16-ounce gloves rather than 12-ounce gloves reduces the chance of injury because the force is distributed
mr Goodwill [35]

Answer:

true

Explanation:

Here we have assumed that increasing the mass of a glove will increase the surface area.

Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by

P=\dfrac{F}{A}

where

F = Force

A = Area to which the force is applied

So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.

Hence, the statement is true.

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3 years ago
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3 years ago
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An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/
Katen [24]
<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}    (1)

Where:

y  is the instrument's final position  

y_{o}=0  is the instrument's initial position

V_{o}=15m/s is the instrument's initial velocity

t is the time the parabolic movement lasts

g=2.5\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of planet X.

As we know y_{o}=0  and y=0 when the object hits the ground, equation (1) is rewritten as:

0=V_{o}.t-\frac{1}{2}g.t^{2}    (2)

Finding t:

0=t(V_{o}-\frac{1}{2}g.t^{2})   (3)

t=\frac{2V_{o}}{g}   (4)

t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}   (5)

Finally:

t=12s

3 0
3 years ago
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