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Inga [223]
3 years ago
6

Help me it is really hard

Mathematics
1 answer:
matrenka [14]3 years ago
8 0
Do you have the problem or a picture
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Percentincreaseof 15 and 20
inna [77]
33.3333333% 20-15=5. 5/15=.333333333*100
8 0
2 years ago
HURRY HELP PLS‼️‼️‼️
Brums [2.3K]

Answer:

Step-by-step explanation:

To solve this problem you need the function

 

h(t) = -16t2 + v0t + h0

where t = time

v0 is the initial velocity, which in our case is 0

h0 = initial height, which in our case is 256

h(t) = 0 since we want to know when the ball will hit the ground.

 

0 = -16 t2 + 256

 

And we can solve for t

 

If we rearrange the terms we see that this is a difference of 2 squares

0 = 256 - 16t2

 

0 = (16-4t)(16+4t)

Setting each factor = 0

16-4t=0       16+4t=4

t = 4             t = -4

 

The second solution is discarded as time cannot be negative.

 

So the ball will hit the ground in 4 seconds.

6 0
2 years ago
A craft store sells boxes of two different varieties of colored pencils. The table shows the number of boxes sold last month. Wh
vlada-n [284]

Answer:

So the answer is 108.75

Step-by-step explanation:

15 * $4.25 = 63.75

12*  $3.75 = 45

63.75 + 45 = 108.75.

Answer:108.75

8 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
Does this graph represent a function? Why or why not?
Morgarella [4.7K]

Answer:

Option D is the correct answer

Step-by-step explanation:

D. Yes, because it passes the vertical line test.

7 0
2 years ago
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