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agasfer [191]
4 years ago
12

What is 11 -2/11 plz answer this

Mathematics
2 answers:
Anestetic [448]4 years ago
8 0

Answer:

9/11

Step-by-step explanation:


Alex787 [66]4 years ago
6 0
9/11 bc 11 minus 2 is 9 so 9/11
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nika2105 [10]
Program 1=65.90
program 2=87.50
8 0
4 years ago
Select the correct answer.
stira [4]
B, because the lines connect at (1,-4) and (4,-1)
3 0
3 years ago
Can someone help and explain this problem to me? I’m stuck
exis [7]

Answer:

  c.  8 units

Step-by-step explanation:

You are to find the y-intercepts of the two functions given, then report the difference between them. The y-intercept is the y-value when x=0.

For f(x), we have ...

  f(0) = 3·2^0 = 3·1 = 3

__

For the table, we can see that x=0 is halfway between x=-2 and x=2, so the y-intercept can be expected to be halfway between y=3 and y=-13. That value for y is ...

  g(0) = (3 + (-13))/2 = -10/2 = -5

That is, the y-intercept of g(x) is -5.

__

The difference between f(0) and g(0) is ...

  f(0) -g(0) = 3 -(-5) = 8 . . . . units

4 0
3 years ago
Integration of (3X(X^2+3)^4) dx<br><img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" " align="absmiddle" c
dimaraw [331]

Answer:


Step-by-step explanation:

\int 3x(x^2+3)^4 \ dx.

It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.

Integration by substitution involves swapping the variable x for another variable which depends on x: u(x). (We are going to choose u for this question).

The very first step is to choose a suitable substitution. That is, an equation u=f(x) which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution u=\text{The Term}.

Your integral contains the term x^2 + 3. The derivative is 2x and (ignoring the constants) we see x is also in the integral and so the substitution u=x^2+3 will unravel this integral!

Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").

u=x^2+3 \Rightarrow \frac{du}{dx}=2x \Rightarrow dx = \frac{1}{2x} du

Then,

\int 3x(x^2+3)^4 \ dx = \int 3x \cdot u^4 \cdot \frac{1}{2x} du = \int \frac{3}{2}u^4\ du.

The substitution has made this integral is easy to solve!

\int \frac{3}{2}u^4\ du= \frac{3}{10}u^5 + C

Finally we can substitute back to get the answer in terms of x:

\int 3x(x^2+3)^4 \ dx = \frac{3}{10}(x^2+3)^5+C

8 0
3 years ago
Evaluate the expression for u=10
Alenkinab [10]

Answer:

-7

Step-by-step explanation:

Evaluate the expression for u=10. Subsitute u for 10 and substract it by 17. 10-17= -7

Your answer is -7

8 0
3 years ago
Read 2 more answers
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