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crimeas [40]
2 years ago
15

Course challenge

Mathematics
2 answers:
krek1111 [17]2 years ago
3 0

Answer:

x=36

Divide the corresponding side (16) by 4/7

irina1246 [14]2 years ago
3 0

Answer:

x=36

Divide the corresponding side (16) by 4/7

Step-by-step explanation:

x=16×9/4=36

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An angle measures 15 degrees more than its complement. Find the measures of the two angles
ale4655 [162]

x = one angle

y = other angle

y = 15+x

complements add to 90 degrees

x+y = 90

substitute for y (15+x)

x + 15+x = 90

combine like terms

2x+ 15 = 90

subtract 15 from each side

2x = 75

divide  each side by 2

x = 75/2

x = 37.5

y = x+15

y = 37.5 + 15

y =52.5

The two angles are 37.5 and 52.5


3 0
3 years ago
Which decimal is equivalent to 2/9?<br> A. 2.2<br> B. 2.9<br> C. 22222<br> D. 0.2
goldenfox [79]

Answer:

The answer is 0.2. It is an irrational number with a repeating 2. It should have a line over the two to represent it repeating.

Step-by-step explanation:

First divide 2 by 9.

Use a calculator or do it by hand.

You get your answer.

3 0
3 years ago
Read 2 more answers
(Translate each sentence into a formula)
Brilliant_brown [7]

Answer:

A=πr2

THIS IS THE ANSWER

PLEASE MARK BRAINLIEST!!!!!

4 0
3 years ago
Pls help for number 6
Vlad1618 [11]
A: 45x + 30y = 1350
Since we don’t know how many adults and children are in the group, we use x and y

b: x-intercept= 30 y-intercept=45
To find the x-intercept you need to isolate the variable. 45x/45 = x
Then you do the same thing to the other side. 1350/45 = 30
So x=30
Same thing with the y-intercept.
30y/30 = y 1350/30 = 45
y=45 (Not really sure what it means by “what they represent” but I thinks it’s that there are 30 adult tickets and 45 children tickets )

c: so our points are (30,0) and (0,45) so you would graph that.
To find how many children tickets were bought if there were 20 adult tickets just look at the photo I put. I don’t know how to explain this.


Hope this helps

7 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
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