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3 years ago

Solve this inequality for x: -46 − 8x > 22.

Mathematics

2 answers:

sveticcg [70]3 years ago

7 0

Answer:

-46-8x>22

22-46=-24

8x/8 -24/8

x=-3

Step-by-step explanation:

uranmaximum [27]3 years ago

7 0

1.1 Pull out like factors :

-68 - 8x = -4 • (2x + 17)

Equation at the end of step

STEP

2.1 Divide both sides by -4

Remember to flip the inequality sign:

2.2 Divide both sides by 2

x+(17/2) < 0

Solve Basic Inequality :

2.3 Subtract 17/2 from both sides

x < -17/2

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Math! Answer to 1&2?

Jobisdone [24]

Answer:

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Step-by-step explanation:

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3 years ago

Students at Nelson middle school are planning a end of a year event of the 150 students in the school 100 would like an athletic

aleksley [76]

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3 years ago

A circular pool if filling with water. Assuming the water level will be 4' deep and the diameter is 20' , what is the volume of

Yuliya22 [10]

35,569.92 L of water is required to fill the pool

Step-by-step explanation:

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8 0

3 years ago

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ipn [44]

Answer:

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3 years ago

Read 2 more answers

Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following

posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{165.9}{6} = 27.65$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

$\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645$

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

$\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%$

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3 years ago