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olga55 [171]
2 years ago
5

. A pedestal is built using a trapezoid-shaped base. Find the area of the trapezoid.

Mathematics
2 answers:
Artist 52 [7]2 years ago
8 0
Should be 18 square meters
Igoryamba2 years ago
4 0

18m^2

area of a trapezoid = (a+b)/2 * h, where a and b are bases 1 and 2, and h is height

(4+8)/2 * 3

= 12/2 * 3

= 6 * 3

= 18

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2) Which expression is equivalent to:<br> y•y3•y2
Nastasia [14]

Answer:

y^6

Step-by-step explanation:

When multiplying terms with exponents that have the same base, the rule is to add the exponents. y * y^3 * y^2 = y^(1 + 3 + 2). (remember that y has a hidden exponent of 1, we just don't write that because it is redundant and unnecessary). y^(1 + 3 + 2) = y^6

hope this helps! <3

3 0
1 year ago
The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
Does anyone know the questions for the dba of pre algebra 2.00?
Oksanka [162]

Answer:

If this is FLVS every lesson has I think its called "Function question" underneath is a question. Thoes questions are for the dba. There are questions at the top of every page of every lesson. Look uo the answers for them! or use the notes most of the time they give you answer to them already. I hope that helps of you have any other questions feel free to ask <3

6 0
2 years ago
Jayden wants to solve the equation n + 67 = 81. He writes the equation n + 67 - 67 = 81 - 67 to find the value of n. Will Jayden
Paladinen [302]
Hello there.

Question: <span>Jayden wants to solve the equation n + 67 = 81. He writes the equation n + 67 - 67 = 81 - 67 to find the value of n. Will Jayden get the correct answer using this equation? 

Answer: n + 67 - 67.
In this part of the equation the 67 would cancel out.
Which leaves n = 81 - 67.
This would get the correct answer to the equation.
Solving the equation meant that he would have to subtract 67 from both sides.
Which he has done.
Solving the equation:
81 - 67 = 14
n = 14.

</span>Hope This Helps You!
Good Luck Studying ^-^
8 0
3 years ago
Complete the following.(a) Find the greatest common factor (GCF) of 63 and 36.хGCF = 0(b) Use the GCF to factor 63 -36.63 – 36 =
morpeh [17]
Answer:

a) The GCF of 63 and 36 is 9

b)

63-36=9\times(7-4)

Explanation:

a) To find the GCF of 63 and 36, we do the following:

Write 63 and 36 as follows:

\begin{gathered} 63=3\times3\times7 \\ 36=2\times2\times3\times3 \end{gathered}

The common factors are:

3\times3

Therefore, the Greatest Common Factor (GCF) is 9

b) To find the factor 63 - 36

63-36=9\times(7-4)

6 0
10 months ago
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