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mr_godi [17]
2 years ago
8

Which is the dependent variable in the following situation?

Mathematics
2 answers:
IrinaVladis [17]2 years ago
8 0
The number of binders
the dependent variable is the one you can change
Leviafan [203]2 years ago
4 0

Answer:

C number of binders because the teacher would have to order binders depending on how many students there are.

Step-by-step explanation:

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The slope of y=6x+3 is 6
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How do you know that the right triangles are the bases of the prism
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Step-by-step explanation:

For the right triangular prism, the base is a right triangle with sides of lengths 3 in, 4 in, and 5 in. If the prism has a height of 6 inches

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2 years ago
John spent 2 hours out of an 8 hour day, painting a car. What percentage of John’s day would this be equal to?
xxMikexx [17]

Answer:

john's just spend 2h out of 8 so thats equal 6h that means he have a 6h days

Step-by-step explanation:

2-8=6

7 0
3 years ago
At a construction job for a house there are 16 painters. Of these painters, 4 of them are painting the
Nikolay [14]

For this case, we have the total of painters is 16, so to determine what percentage is painting the interior of the house, we make a rule of three:

16 ---------------> 100%

4 -----------------> x

Where "x" represents the% of painters who paint the interior of the house.

x = \frac {4 * 100} {16}\\x = 25

Thus, 25% of painters are painting the interior of the house.

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25%

8 0
3 years ago
Given x^2 + y^2 = 36 and xy = -10 find x + y.
9966 [12]
This looks fun

ok so
we will use subsitution
xy=-10
divide both sides by x or y (I will choose y)
x=-10/y

sub -10/y fo x

(-10/y)^2+y^2=36
100/(y^2)+y^2=36
times both sides by y^2
100+y^4=36y^2
minus 36y^2 from both sides
y^4-36y^2+100=0
(y^2)^2-36(y^2)+100=0
quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
x=\frac{-(-36)+/- \sqrt{(-36)^2-4(1)(100)} }{2(1)}
x=18+/- 4\sqrt{14}

sub
y=-10/x
y=\frac{-10}{18+/- 4\sqrt{14}}

so x+y=18+/- 4\sqrt{14}+\frac{-10}{18+/- 4\sqrt{14}}
multiply first number by \frac{18+/- 4\sqrt{14}}{18+/- 4\sqrt{14}} and add them

x+y=\frac{(18+/- 4\sqrt{14})(18+/- 4\sqrt{14})-10}{18+/- 4\sqrt{14}}
or
x+y=\frac{81+22 \sqrt{14} }{5} or \frac{81-22 \sqrt{14} }{5}




8 0
3 years ago
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