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Nitella [24]
2 years ago
8

A laundry basket contains 10 socks, of which 2 are red. What is the probability that a randomly selected sock will be red? Write

your answer as a fraction or whole number.
Mathematics
1 answer:
algol132 years ago
3 0

Answer:

you get a pair of red socks. There are 10 socks in the drawer, and 2 are red. Therefore the probability that the first one will be red is 2/10 = 1/5.

Step-by-step explanation:

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The volume of a sphere is 2,240 yd^3. What will be the new volume in the dimensions are multiplied by 1/4?
Veseljchak [2.6K]

Answer:

34.98yd^3

Step-by-step explanation:

Volume of a sphere V=4/3πr3

Where V = 2240yd^3

π = 3.14

2240 = 4/3×3.14×r^3

2240 = 4.1866r^3

r^3 = 2240/4.1866

r^3 = 534.784

r = ( 534.784 )^1/3

r = 8.1169

Since each dimension is to be multiplied by 1/4

Hence, 1/4×8.1169

r = 2.029.

New volume will be

V = 4/3×3.14×2.029^3

V = 4/3×3.14×8.3558

V = 34.98yd^3.

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3 years ago
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STatiana [176]

Answer:

v

Step-by-step explanation:

8 0
3 years ago
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Please help with the problem!
madam [21]

Answer:

3(2*-1)^2

solved is: 12

Step-by-step explanation:

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3 years ago
Please help me!! <br> solve 31 = x + 25.5
serious [3.7K]

Answer:

x = 5.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

31 = x + 25.5

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 25.5 on both sides:                    5.5 = x
  2. Rewrite:                                                      x = 5.5
6 0
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I need help on this question, someone please help!!
Tju [1.3M]

Answer:

y=−x−1/3x−8

Step-by-step explanation:

y=8x−1/3x+1

To find the inverse function, swap x and y, and solve the resulting equation for x.

If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.

Now, solve the equation x=8y−1/3y+1 for y.

y=−x−1/3x−8

Sorry I was in a rush and couldn't do the fractions as formulae. Hope it helped anyways.

7 0
3 years ago
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