Question

PLEASE I NEED HELP!

Answer 1

Answer:

$\pi (5\: \sf in)^2\left(\dfrac{30^{\circ}}{360^{\circ}}\right)$

π(5in)² 30 over 360

Step-by-step explanation:

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

(where $\theta$ is the angle and r is the radius)

Given:

• $\theta$ = 30°
• r = 5 in

Substituting these values into the equation:

$\begin{aligned}\implies\textsf{Area} &=\left(\dfrac{30^{\circ}}{360^{\circ}}\right) \pi \cdot (5\: \sf in)^2\\\\ & = \pi (5\: \sf in)^2\left(\dfrac{30^{\circ}}{360^{\circ}}\right)\\\\ & = \pi \cdot 25\:(\sf in^2) \cdot \dfrac{1}{12}\\\\ & = \dfrac{25}{12} \pi \:(\sf in^2) \\\\ & = 6.54\: \sf in^2\:(nearest\:hundredth) \end{aligned}$

Answer 2

π(5in)² * 30 over 360 can be used to determine sector area.

$\sf sector \ area \ : \dfrac{\theta}{360} *\pi *radius^2$

# radius = 5 inches

# angle = 30 degrees

sector area:

$\hookrightarrow \sf \dfrac{30}{360} *\pi *5^2$

$\hookrightarrow \sf \dfrac{1}{12} *\pi *25$

$\hookrightarrow \sf \dfrac{25}{12}\pi$

$\hookrightarrow \sf 6.54 \ inch^2$