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Nutka1998 [239]
3 years ago
11

Which net represents this triangular prism?

Mathematics
2 answers:
Anarel [89]3 years ago
3 0

Answer:

this one.............

frosja888 [35]3 years ago
3 0

Answer:

top right

Step-by-step explanation:

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Can someone please help me. I think the answer is Y= -14 but I’m not sure
Sergeeva-Olga [200]

Answer:

yep your correct!

Step-by-step explanation:

i did 5(-2) -4

which is -10 -4

and that will equal -14!

hope this helps u!

3 0
3 years ago
Read 2 more answers
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.
zhannawk [14.2K]

Answer:

a) 0.6032

b)

Lower limit: 0.48

Upper limit: 0.72

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Question a:

In a random sample of 63 professional actors, it was found that 38 were extroverts.

We use this to find the sample proportion, which is the point estimate for p. So

\pi = \frac{38}{63} = 0.6032

Question b:

Sample of 63 means that n = 63

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6032 - 1.96\sqrt{\frac{0.6032*0.3968}{63}} = 0.4824

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6032 + 1.96\sqrt{\frac{0.6032*0.3968}{63}} = 0.724

Rounding to two decimal places:

Lower limit: 0.48

Upper limit: 0.72

7 0
3 years ago
If a carpet sells for $15.50 per square yard, how much will it cost to cover a room
algol13
The carpet will cost $310
4 0
3 years ago
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What is the surface area of the triangular prism?
stepladder [879]

Answer:

<h2>135 ft²</h2><h2 />

Step-by-step explanation:

surface area = bh + L(s1 + s2 + s3)

where b = 2.5 ft.

           h = 6 ft.

          s1 = 6.5 ft.

          s2 = 6 ft.

         s3 = 2.5 ft.

          L = 8 ft.

<u>plugin values into the formula: </u>

A = 2.5*6 + 8(6.5 + 6 + 2.5)

   = 15 + 8(15)

   = 135 ft²

6 0
3 years ago
What is the best way to display a set of data with a wide range, where we want to be able to find the measures of central tenden
zhuklara [117]
The answer for your question is histogram<span>
</span>
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3 years ago
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