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nalin [4]
2 years ago
8

Find and interpret the mean absolute deviation of the data. 8,12,4,3,14,1,9,13

Mathematics
2 answers:
melomori [17]2 years ago
7 0

Answer:

8

Step-by-step explanation:

8+12+4+3+14+1+9+13=64, 64/8=8

Colt1911 [192]2 years ago
4 0

Answer:

44.6

Step-by-step explanation:

First, to answer this question, we need to find the mean of this data set. <u><em>When finding the mean, you use the same process you use when averaging.</em></u>

So we would do: 8 + 12 + 4 + 3 + 14 + 1 + 9 + 13/8

Our new fraction turns into 64/8, which we can then divide to give us 52.625. We can round up our new number to give us 52.6

We now need to find the absolute value of the difference between each data value and mean. In simple terms, we use the answer we got from our fraction and subtract it from each number in our cluster of numbers/data set. <u><em>Keep in mind when subtracting you will get some negative numbers, but in this scenario we take away any negative sings, so we don't end up with any negative numbers.</em></u>

<u><em /></u>

8 - 52.6 = -44.6 = 44.6

12 - 52.6 = -40.6 = 40.6

4 - 52.6 = -48.6 = 48.6

3 - 52.6 = -49.6 = 49.6

14 - 52.6 = -38.6 = 38.6

1 - 52.6 = -51.6 = 51.6

9 - 52.6 = -43.6 = 43.6

13 - 52.6 = -39.6 = 39.6

Finally, we need to to the same process we used in our first step, <u><em>just use the new numbers we have instead of our old numbers.</em></u>

This gives us 356.8/8, which when divided, will leave us with 44.6.

<u><em>Therefore, our answer is 44.6 </em></u>

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WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

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4 years ago
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Lapatulllka [165]
Area is 1/2•b•h so 25
7 0
3 years ago
Can someone help me with this math homework please!
Zepler [3.9K]

Answer:

Step-by-step explanation:

1) Least common denominator of 4 and 2 is 4

To eliminate the fraction, each term should be multiplied by 4

ANS:option c

2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years

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Add 'b' to both sides

4b + b + 6 = 2 + 4

5b + 6 = 6

Subtract 6 from both sides

5b = 6 - 6

5b = 0

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Ans : Option b

4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100

Ans: option d

5) y +6 = -3y + 26

Add 3y to both the sides

y + 6 + 3y =  26

y + 3y + 6 = 26

4y + 6 = 26

Subtract 6 from both sides

4y = 26-6

4y = 20

Divide bothe sides by 4

y = 20/4

y = 5

Ans: option c

6) '2x' is  subtracted from both side of the equation.

Ans: option a - subtraction property of equality

                     

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