The correct answer is:
DNA template 3'– ……… –5'
RNA transcript 5'– ……… –3'
Protein product H2N– ……. –COOH
In nucleic acids, DNA and RNA 5’ end refers to phosphate group attached to the 5′ carbon of the ribose ring, while 3’ end refers to the ribose -OH substituent. Nucleic acids can only be synthesized in the 5′-to-3′ direction, which means that the DNA template is 3’—5’. Translation of the protein by the ribosome will also proceed in a 5′ to 3′ direction, which means that the mRNA template is 3’—5’.
The protein during the synthesis is extend from its N terminus toward its C terminus.
Answer:
Thymidine dimers is likely to be repair as soon as it is originated but if left unrepaired then it causes frame shift mutations.
Explanation:
In case of Bacterium if UV irradiation induces covalent linkage of two thymidine present adjacently to each other or on a single strand to make thymidine dimers.
These either excised via DNA repair enzyme like Endonuclease V and the proof reading activity of DNA polymerase I enzyme help in incorporation of nucleotide by taking the unmutated original strand as a template.
These dimers if not excised before second round of replication than the sequence of newly synthesized strand will be altered. As DNA polymerase III enzyme read thymidine dimers as single thymidine nucleotide and incorporate only 1 adenine in the newly synthesizing complementary strand which results in frame shift mutations
It is the mutation in which reading frame of codons is shifted or altered due to deletion or addition of a single nucleotide.
When organic molecules decompose, energy is released.
The correct processes and components of the carbon cycle is given in the image attached .
The genotype at the Q gene is Homozygous
