I believe it is x-4 but might be totally wrong
The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
brainly.com/question/1770447
#SPJ1
1.25j+5.25 would be the answer. just combine like terms
Answer: (A(x2+1)x-3)^=134
Step-by-step explanation: what me my brother did was just look it up
Answer:
c
Step-by-step explanation:
please see attached with explanation
hope it helps