OKAY BRAINLY 3 MORE MATH QUESTIONS AND THEN IM OUT OF YOUR HAIR FOR TONIGHT AND YOU CAN STOP SENDING ME WARNINGS!!!!1

can someone help me understand this, please? For some reason my answer is correct but I need to understand how did I found the c

Morgarella [4.7K]

Answer with step-by-step explanation:

The way the question is worded, this actually shouldn't be correct. The correct answer should be $3:4$ .

Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.

Why?

By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.

Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are $\overline{RS}$ and $\overline{AB}$ .

The ratio of $\overline{RS}:\overline{AB}$ is $18:24\implies \boxed{3:4}$ .

The reason why it ideally should be $3:4$ and not $4:3$ is because the question states $RTSU\sim ABCD$ , which mentions $RSTU$ first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.

3 0

2 years ago

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$

5 0

3 years ago

Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in

tatuchka [14]

Answer:

The equation representing how old Monique son is $\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

$q(t) = \hat q \times t + q_o$

where;

$q_o$ = initial height of Monique's son

$\hat q$ = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

$\hat q = 2 \dfrac{5}{8} \ in/yr$

$\hat q = \dfrac{21}{8} \ in/yr$

Then; from the equation $q(t) = \hat q \times t + q_o$

$34 = \dfrac{21}{8} \times 0 + q_o$

$q_o = 34\ inches$

The height of the son as a function of the age can now be expressed as:

$q(t) = \dfrac{21}{8} \times t + 34$

Then:

Making t the subject;

$q - 34 = \dfrac{21}{8} \times t$

$t = \dfrac{8}{21}(q-34)$

and the age of the son i.e. ( a (in years)) is:

a = 2 + t

So;

$\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

SO;

if q (growth rate) = 50 inches tall

Then;

$\mathbf{a = 2 + \dfrac{8}{21}(50-34)}$

$\mathbf{a = 2 + \dfrac{8}{21}(16)}$

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0

2 years ago

A set of three lines that has one point of intersection

ryzh [129]

This construction called a pencil of lines. That figure can have 3,4,5.... any number of straights lines. The main rule is their common point. And it looks like spokes of a wheel. Here you can find a lot of vertical angles and rays.

6 0

3 years ago

How is this a non proportional relationship y=2x 4?

saveliy_v [14]

Y=2x +4 is non proportional because b does not equal 0
The b in the equation is 4
As long as the y intercept is not more or less than 0, than it will be proportional

5 0

3 years ago