sin (x) = -1
arcsin (-1) = x
x = -90
and multiples of 360
x =-90, 270,....
x =-90 + 360n where n is an integer
or in radians
-pi/2 + 2*pi *n where n is an integer
If the term in the middle is 16x^2
6x^2-24x-16x^2-9x+1 =
-10x^2-33x+1
Your answer is False because obtuse angles are wide acute angles are right in the like this:^ but turn it to the west a right angle is like an L so your answer is False.
Your answer is False or B.
Okay so you do p(x) -q(x) and you get (x)^2-5x hope this helps. (Also hope that trigonometry I'm taking comes through lol)
