Weight in what form pounds?
About 20.7 minutes you get to spend with each dog for a total of 145 minutes.
Answer:
12
Step-by-step explanation:
For our problem since we only in 10 am:
I'm going to let x=4 represent the time 10:04 am
which means I'm going to let x=17 represent 10:17am.
So when x=4, y=23 miles and when x=17,y=179 miles.
You have two points.
You can use the formula
.
Or just line the points up vertically and subtract them vertically, then put 2nd difference over first difference. Like this:
( 17 , 179)
-( 4 , 23)
-----------------------
13 156
So the slope is 156/13=12 miles/hour.
Each paper cup is a cone.
The volume if a cone is (1/3) (pi) (radius)² (height)
Notice, in the picture they labeled the <em>diameter</em> of the cup = 8 cm.
But we need the<em> radius</em>. that's 1/2 of the diameter = 4 cm.
So, the volume of these paper cups is
(1/3) (pi) (4cm)² (11 cm) = about <em><u>184 cm³</u></em>
=====================
It says that tons of lemons have been sacrificed, and you have
about 37,850 cm³ of lemonade.
How many cups will that fill ?
37,850 cm³ / 184 cm³ = about <em>205 cups</em>.
========================
How many packs of cups do you need to buy ?
Unfortunately, they only come in packs of 50.
1 pack = 50 cups . . . . . not enough
2 packs = 100 cups . . . not enough
3 packs = 150 cups . . . not enough
4 packs = 200 cups . . . oh so close but still not enough
You need to buy <em>5 packs = <u>250 cups</u></em>.
=================================
It started raining, so you only sold 80% of the lemonade that you had.
80% means 0.80
"of" means "times"
You started out with 37,850 cm³ .
You sold (0.8) x (37,850 cm³) = about <u>30,280 cm³</u> of it.
How many cups did you fill with that much lemonade ?
(Remember, each cup holds about <u>184 cm³</u>.)
30,280 cm³ / 184 cm³ = about <u>164 cups sold</u>.
You bought 250 cups to start out.
You sold 164 cups of lemonade.
You had (250 bought - 164 used) =
<em>86 clean, unused paper cups, still in the wrappers, left over</em>.
probability that the card drawn is:
- an ace or a king = 0.1538
- a king or a diamond = 0.3269
<u>Step-by-step explanation:</u>
Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:
A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.
![probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7BNumber-of-%28ace%2Bking%29-cards%7D%7Btotal-number-of-cards%7D)
⇒ ![probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7BNumber-of-%28ace%2Bking%29-cards%7D%7Btotal-number-of-cards%7D)
⇒ ![probability = \frac{8}{52}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7B8%7D%7B52%7D)
⇒ ![probability = 0.1538](https://tex.z-dn.net/?f=probability%20%3D%200.1538)
A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.
![probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7BNumber-of-%28ace%2Bking%29-cards%7D%7Btotal-number-of-cards%7D)
⇒ ![probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7BNumber-of-%28ace%2Bking%29-cards%7D%7Btotal-number-of-cards%7D)
⇒ ![probability = \frac{(13+4=17)}{52}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7B%2813%2B4%3D17%29%7D%7B52%7D)
⇒ ![probability = \frac{(17)}{52}](https://tex.z-dn.net/?f=probability%20%3D%20%5Cfrac%7B%2817%29%7D%7B52%7D)
⇒ ![probability =0.3269](https://tex.z-dn.net/?f=probability%20%3D0.3269)
Therefore, probability that the card drawn is:
- an ace or a king = 0.1538
- a king or a diamond = 0.3269