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Anton [14]
3 years ago
5

Please help with a multiple choice question!!

Mathematics
1 answer:
Maslowich3 years ago
3 0
B and C. From graph relationship A = Y/X = (8-4)/(4-2) = 2.
Therefore only options B and C has agreater relationship than Relationship A.
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In the figure below, segment AC is congruent to segment AB.
sattari [20]

Answer:

Option B is correct.

Angle DAC is congruent to angle DAB

Step-by-step explanation:

Given: Segment AC is congruent to segment AB.

In  ΔABD and ΔACD

AB \cong AC    [Given]

[Congruent sides have the same length]

AB = AC         [Side]

AD = AD        [Common side]

\angle DAC =\angle DAB      [Angle]

Side Angle Side(SAS) Postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

Then by SAS,

\triangle ABD \cong \triangle ACD

By CPCT [Corresponding Parts of congruent Triangles are congruent]

then;

\angle ABD \cong \angle ACD

therefore, only statement which is used to prove that angle ABD is congruent to angle ACD is: Angle DAC is congruent to DAB

4 0
4 years ago
Read 2 more answers
Can you please give me the cords of the points when the figure is rotated 90 degrees clockwise.
crimeas [40]
Don't you mean "coords," or (better yet) "coordinates?"

Look at line DG as an example.  It's vertical.  If you rotate the whole figure clockwise, then line DG becomes the horiz. line D'G.'  G' would have the coordinates (-1,-1), and D' (5,-1).  Plot these points G' and D' and see whether or not you agree.

3 0
3 years ago
Help please I asp !!!
Mice21 [21]

Answer:

Step-by-step explanation:

1

8 0
3 years ago
Which function has a different range than the function f(x)=bx?
kodGreya [7K]
The answer is D but i could be wrong
3 0
3 years ago
Solve the inequality.<br><br> Please help.
Fantom [35]

Answer:

2 < x <_ 3.5

Step-by-step explanation:

First, find the value of x by writing it as an equation. Then, use 0 as x to determine the correct inequality.

3 0
3 years ago
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