Help?? I could really use it

Mathematics

1 answer:

Lynna [10]2 years ago

4 0

Answer:

16.5 m

Step-by-step explanation:

The triangle shown in the figure is a right triangle, so we can use the Pythagoreas Theorem.

a² + b² = c²

a² + 32² = 36²

a² + 1024 = 1296

a² = 272

a = √272

a = 16.5

Answer: 16.5 m

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Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (

MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em> If $\large \bar x$ is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

$\large [\bar x - s, \bar x +s]$

around 95% of the data must fall in the interval

$\large [\bar x -2s, \bar x +2s]$

around 99.7% of the data must fall in the interval

$\large [\bar x -3s, \bar x +3s]$

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0

2 years ago

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of (w circle r) (x)?

VashaNatasha [74]

Answer:

$(-\infty, 0)$