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3 years ago

8

What is £56 divided in a ratio of 3:5?

1 answer:

Luda [366]3 years ago

7 0

First, add the ratio together to get the denominator of the fraction you will use to determine the share. 3+5= 8. Now, you have two fractions: 3/8 and 5/8. Next, just find 3/8 and 5/8 of 56 to get your answers:
(56÷8)×3= <span>£21
</span>and
(56÷8)×5= <span>£35</span>

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(a) $x^{-5}$

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Solution:

To write each of the given expression in the form $ax^n$ :

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Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

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(c) $\frac{28x^6}{21x^2}$

Divide numerator and denominator by the common factor 7, we get

$$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}$

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3 years ago

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Answer:

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2 years ago

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3 years ago

Read 2 more answers

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is $14.28days^{-1}$

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

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4 years ago