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3 years ago

What is £56 divided in a ratio of 3:5?

1 answer:

7 0

First, add the ratio together to get the denominator of the fraction you will use to determine the share. 3+5= 8. Now, you have two fractions: 3/8 and 5/8. Next, just find 3/8 and 5/8 of 56 to get your answers:
(56÷8)×3= <span>£21
</span>and
(56÷8)×5= <span>£35</span>

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3 years ago

How much does 5 pounds for $2.49 equal

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The question is saying that if you buy 5 lbs, you have to pay $2.49. That means that 1 lb is $2.49/5 which (rounded to the nearest cent) is $0.50

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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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3 years ago

Sally walked 3/4 mile east from her house to the bank, then she walked 1/3 mile west to the gift shop. From the gift shop she wa

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3 years ago

8. The Last Supper

Salsk061 [2.6K]

The number of possible seats is an illustration of permutation

There are 1728 possible sitting arrangements

<h3>How to determine the number of seats</h3>

From the question, we have the following highlights:

Chris can only take 1 seat (i.e. the central seat)
Jo can take 2 seats (i.e. the seats adjacent the central seat)
Alex, Barb and Dave can take 3! number of seats
Eddie, Fred, and Gareth can take 3! number of seats on the right of Chris.
The remaining 4 adults do not have preference, then they can seat in 4! ways

So, the number of sitting arrangement is:

$n = 1 * 2 * 3! * 3! * 4!$

Evaluate the product

$n = 1728$

Hence, there are 1728 possible sitting arrangements