All categories

2 years ago

Need Help ASAP! no links please

Mathematics

1 answer:

tekilochka [14]2 years ago

5 0

Answer:

Step-by-step explanation:

Each of the five spaces on the spinner are equal so the theoretical probability for one space (Q) is 1/5. For the experimental probability, they spun it 15 times and 4 times it landed on Q so 4/15 times.

You might be interested in

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

Dmitrij [34]

Answer:

$V = \frac{450L - 6 L^{3} }{10}$

Step-by-step explanation:

The volume of a cuboid can be determined simply by the formula: V= LWH

(where: L is length, H is height and W is width).

In this particular case the base is a square, which means the length and width are equal. Hence we can modify the equation of volume:

$V = L^{2} H$

Now we need to find the value of H in terms of L. For this we can develop the equation for cost incurred in building the storage shed. We find the area of each side of the cuboid, and then we multiply it by cost per square feet to find the total cost incurred; as shown below:

Area:

Base: $L$ × $L = L^{2}$

Roof: $L$ × $L = L^{2}$

Side: $4 H$ × $L = 4HL$ (we have considered all four sides)

Cost:

Base: 4 $L^{2}$

Roof: 2 $L^{2}$

Side: $2.50 * 4HL = 10 HL$

Total cost:

4 $L^{2}$ + 2 $L^{2}$ + 10 $HL$ = 450

We simplify this equation further:

6 $L^2$ + 10HL = 450

10HL = 450 - 6 $L^2$

$H = \frac{450- 6 L^2}{10L}$

We now have the value of H, which we can substitute in the formula of Volume we deduced earlier:

substituting $H = \frac{450-6L}{10L}$ in $V = L^{2} H$ :

$V = L^2$ × $\frac{450 - 6L }{10L}$

Simplifying it further:

$V = L$ × $\frac{450 - 6L}{10}$

$V= \frac{450L - 6L^3}{10}$ is the final answer.

3 0

3 years ago

Graph the following inequality on the number line above. 3x < 12

irina [24]

Take the three and divide it with the 12 which would get you 4 so put a open circle Above the 4 and make the line go to the left I think I hope this will help

4 0

3 years ago

A student ticket to the movie cost $4

Shalnov [3]

Answer:(X x 4)=

Step-by-step explanation:

Basically u times how many tickets u need times how much it cost

Example( 1ticket X 4dollars) =4 dollars

8 0

3 years ago

Read 2 more answers

The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax

charle [14.2K]

First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

$\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx$

Let $u=e^x$ , so that $\mathrm dx=\dfrac{\mathrm du}u$ , and the integral is equivalent to

$\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du$

The integrand is continuous everywhere except $u=0$ , but that's okay because we have $\lim\limits_{u\to0^+}\frac{\sin u}u=1$ . This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

$\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx$

By the same substitution as before, we can write this as

$\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du$

The half-angle identity for sine allows us to rewrite as

$\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du$

and replacing $v=2u$ , $\dfrac{\mathrm dv}2=\mathrm du$ , we have

$\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv$

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

$\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))$

where $\gamma$ is the Euler-Mascheroni constant and $\mbox{Ci}$ denotes the cosine integral function.

5 0

4 years ago

Write the nth term of the following sequence in terms of the first term of the sequence. PLEASE HELP DUE IN 6 DAYS!!!!!!!

nalin [4]

Answer:

a + 4(n-1)

Step-by-step explanation:

The first term is a+4, the second term is a+8, the third term is a+12, etc.

A common theme that we can notice is that we add 4 for each term. For example, the second term (t₂) equals t₁+4, the third term equals t₂+4 (as a+4+4 = a+8), and so on. Another way of writing this is that we multiply 4 by (term number - 1) and add that to a. We can write this as

4 * (n-1) + a

7 0

3 years ago