All categories

3 years ago

The number 6,253 rounded to the nearest hundred is —————

Mathematics

2 answers:

artcher [175]3 years ago

7 0

Answer:

6,300

Step-by-step explanation:

The hundredth position is the 2, The third number from the end of the number. You have to round up 253 to either 300 or 200. Since 253 is bigger than 250, you need to round up to 6300.

faust18 [17]3 years ago

6 0

Answer:

6300

Step-by-step explanation:

253 is closer to 300 than to 200

You might be interested in

Beth has 250 comic books in her collection. She begins to sell 20 of them each week. Martin has 80 comic books in his collection

guapka [62]

Answer:

250 - 20 < 80 + 15x

Step-by-step explanation:

Given that

Beth has 250 books and 20 books sold each week

While on the other hand, Martin has 80 books and sell 15 books each week

Let us assume each week be x

Now the equations are

Beth 250 - 20x

Martin 80 + 15 x

Now the inequality would be

250 - 20 < 80 + 15x

8 0

3 years ago

Which is a linear function?

oee [108]

Answer:

Step-by-step explanation:

A linear function describes a straight line with constant gradient. Hence A is the answer as it has a constant gradient of -1 .

B is wrong as the graph has an undefined gradient.

C is wrong as it has an increasing gradient.

D is wrong as it does not have a constant gradient too.

7 0

3 years ago

Y=6(x-7)^2……. any one know this ?

alex41 [277]

Answer: 6x^2-84x+294

Step-by-step explanation:

Use the foil method to solve (x-7)^2 and then multiply your result by 6.

4 0

3 years ago

Read 2 more answers

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$