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2 years ago

Given circle E with diameter CD and radius EA. AB is tangent to Eat A.

Mathematics

1 answer:

Tatiana [17]2 years ago

7 0

The triangle ACD is the right angle since it is a triangle in a semicircle. The length of AC from the diagram is 21.9feet

<h3>Application of pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the square of the other two sides

From the given circle, the triangle ACD is right angle since it is a triangle in a semicircle

Given the following

Hypotenuse = 26 feet = CD
Base side = AD = 14ft

Required

Length AC

Use the theorem

26^2 = 14^2 + AC^2

AC^2 = 676 - 196
AC^2 = 480
AC = 21.9feet

Hence the length of AC is 21.9feet

Learn more on pythagoras theorem here: brainly.com/question/343682

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QRST is a square. PQ = 2√ RU = 4 What is the length of SU? Round to the nearest tenth.

777dan777 [17]

Answer:

$SU=3.5\ units$

Step-by-step explanation:

step 1

In the isosceles right triangle PQT

PQ=PT ----> because is an isosceles triangle

Applying the Pythagoras Theorem

we have

$PQ=PT =\sqrt{2}\ units$

$QT^{2}=PQ^{2} +PT^{2}$

substitute the values

$QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}$

$QT^{2}=4$

$QT=2\ units$

step 2

In the square QRST

$RS=QT=2\ units$

step 3

In the right triangle RSU

Applying the Pythagoras Theorem

$RU^{2}=RS^{2} +SU^{2}$

we have

$RU=4\ units$

$RS=2\ units$

substitute the values and solve for SU

$4^{2}=2^{2} +SU^{2}$

$SU^{2}=4^{2}-2^{2}$

$SU^{2}=12$

$SU=2\sqrt{3}\ units$

$SU=3.5\ units$

8 0

3 years ago

A sector of a circle of 7cm has an area of 44cm².calculate the angle of the sector,correct to the nearest degree π =22\7

Hitman42 [59]

Answer:

$\theta=102.85^{\circ}$

Step-by-step explanation:

Given that,

The radius of circle, r = 7 cm

The area of sector, A = 44cm²

We need to find the angle of the sector. The formula for the area of sector is given by :

$A=\dfrac{\theta}{360}\pi r^2$

Solve for $\theta$ .

$\theta=\dfrac{360A}{\pi r^2}\\\\\theta=\dfrac{360\times 44}{\dfrac{22}{7}\times 7^2}\\\\\theta=102.85^{\circ}$

So, the angle of the sector is equal to $102.85^{\circ}$ .

7 0

3 years ago

If FGH QRS, find the measure of Q A. 9 B.28 C.11 D.34

Ne4ueva [31]

Answer:

28°

Step-by-step explanation:

Since ΔFHG ≅ QRC, the corresponding angles are congruent:

∠F = ∠Q
(2x + 10)° = (3x + 1)°
3x - 2x = (10 - 1)°
x = 9°

Then, the angle Q measures:

∠Q = (3*9 + 1)° = 28°

6 0

3 years ago

Help me out pleaseeeee

vladimir2022 [97]

Answer:

86 degrees

Step-by-step explanation:

just do 110 degrees - 24 degrees to get 86 degrees

6 0

3 years ago

PLease help with this fast

lilavasa [31]

It is B that your looking for

5 0

3 years ago

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