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Gala2k [10]
3 years ago
10

Which gaseous giants did renaissance scientists such as galileo know about? select two options. jupiter mars neptune saturn uran

us
Physics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

Jupiter and Saturn

Please Mark Brainliest If This Helped!

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Two climbers are on a mountain. Simon, of mass m, is sitting on a snow covered slope that makes an angle θ with the horizontal.
elena-14-01-66 [18.8K]

Answer:

Explanation:

It is required that the weight of Joe must prevent Simon from being pulled down . That means he is not slipping down but tends to be towed down . So in equilibrium , force of friction will act in upward direction on Simon.

Let in equilibrium , tension in rope be T

For balancing Joe

T = M g

For balancing Simon

friction + T = mgsinθ

μmgcosθ+T = mgsinθ

μmgcosθ+Mg = mgsinθ

M = (msinθ - μmcosθ)

M = m(sinθ - μcosθ)

5 0
3 years ago
A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m
olasank [31]

Answer:

Explanation:

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

mgh = ½mv²

v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s

7 0
3 years ago
Differentiate can you help me plzzzzzzz​
Schach [20]

Explanation:

Acceleration and the other term are the same physical phenomenon - just with opposite affects. Acceleration increases velocity, while the other term that begins with the letter "R" reduces.

***(Brainly's language filter is blocking the use of the second term in my answer.)***

Acceleration is defined as the rate of change of the velocity of an object per unit of time...

a = \frac{dv}{dt}

Acceleration would be a POSITIVE (+) quantity, while the r-word would be negative (-).

4 0
4 years ago
A diver, of mass 40kg, climbs up to a diving platform 1.25m high. What’s her KE
Leona [35]

Explanation:

The formula for KE ( Kinetic Energy ) is : 1/2 mv²

Solution:

  • First we solve for v ( velocity ) using the formula 2gh, where g is gravity [ 9.8 m/s² ] and h is height [ 1.25 m ]

= 2 ( 9.8 m/s² × 1.25 m ) = 24.5 m/s

  • The velocity is 24.5 m/s.

  • Now solve for KE using the formula 1/2 mv²

= 1/2 ( 40 kg × 24.5m/s ² )

= 1/2 ( 40 kg × 600.25 )

= 1/2 ( 24,010 )

= 12,005 Joules

  • The diver's kinetic energy is 12,005 J.

6 0
2 years ago
A CD has a mass of 17 g and a radius of 6.0 cm. When inserted into a player, the CD starts from rest and accelerates to an angul
Stells [14]

Answer:

τ =9.41 * 10⁻⁴ N*m

Explanation:

Kinematics of the CD

The CD rotates with constant angular acceleration and its angular acceleration is calculated as follows:

\alpha = \frac{\omega_{f}- \omega_{i}}{t}   Formula (1)

Where:

α : angular acceleration. (rad/s²)

ωf: final angular velocity  (rad/s)

ωi : initial angular velocity  (rad/s)

t = time interval (s)

Data

ωf= 20 rad/s

ωi =0

t = 0.65 s.

Calculating of the angular acceleration of the CD

We replace data in the formula (1)

\alpha = \frac{20 -0}{0.65}

α  = 30.77 rad/s²

Newton's second law  in rotation:

F = ma has the equivalent for rotation:

τ = I * α   Formula  (2)

where:

τ : It is the net torque applied to the body.  (N*m)

I :  it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Calculating of the moment of inertia  of the CD

The moment of inertia of a disk with respect to an axis perpendicular to the plane  and passing through its center is calculated by the following formula:

I = (1/2) M*R² Formula (3)

Data

M= 17 g = 17/1000 kg = 0.017 kg  : CD mass

R= 6.0 cm= 6/100 m = 0.06 m : CD  radius

We replace data in the formula (3) :

I = (1/2) ( 0.017 kg)*(0.06 m)² = 3.06 * 10⁻⁵ kg*m²

Calculating of the  net torque acting on the CD

Data

α  = 30.77 rad/s²

I =  3.06 * 10⁻⁵ kg*m²

We replace data in the formula (2) :

τ = I * α

τ =( 3.06 * 10⁻⁵ kg*m²) * (30.77 rad/s²)

τ =9.41 * 10⁻⁴ N*m

3 0
3 years ago
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