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slamgirl [31]
3 years ago
15

A train is travelling along a straight track at constant velocity from Western Station to Eastern station. The mile markers incr

ease towards the east. A passenger notices that, at mile marker 25, the reading on this stopwatch is 15 minutes, and at mile marker 60, the reading on this stopwatch is 45 minutes. What is the velocity of the train in meters per second
Physics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

Explanation:

Displacement of train = 60 - 25 = 35 mile

= 35 x 1.6 = 56 km

duration of time = 45 - 15 = 30 minutes

= 30 x 60 = 1800 s

velocity of train = displacement / time

= 56 / 1800 = .03111 km /s

= 31.111 m / s

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An electrical appliance has a resistance of 40 Ω. When this electrical appliance is connected to a 220 V supply line, the curren
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Answer:

b) 5.5 A

Explanation:

Use Ohm's Law to solve for I:

I=V/R

V is voltage and R is resistance

V=220V

R= 40 Ω

I=220V/40Ω

I= 5.5 Amps

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What is the coefficient for titanium tetrachloride when the equation below is balanced?
Alexus [3.1K]

the coefficient of TiCl4 would be 1

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A string vibrates at a frequency of 20Hz. what is its period?
Andreas93 [3]
We know, Period = 1/frequency = 1/20 sec.

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3 years ago
Two cars are traveling at the same speed of 27 m/s on a curve thathas a radius of 120 m. Car A has a mass of 1100 kg and car B h
Lera25 [3.4K]

Answer:

a_{cA} = 6.075  m/s²

a_{cB} = 6.075  m/s²

F_{cA} = 6682.5 N

F_{cB} = 9720 N

Explanation:

Normal or centripetal acceleration measures change in speed direction over time. Its expression is given by:

a_{c} = \frac{v^{2} }{r}  Formula 1

Where:

a_{c} : Is the normal or centripetal acceleration of the body  ( m/s²)

v: It is the magnitude of the tangential velocity of the body at the given point

.(m/s)

r: It is the radius of curvature. (m)

Newton's second law:

∑F = m*a Formula ( 2)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

Data

v_{A} = 27 \frac{m}{s}

v_{B} = 27 \frac{m}{s}

m_{A} = 1100 kg

m_{B} = 1600 kg

r= 120 m

Problem development

We replace data in formula (1) to calculate centripetal acceleration:

a_{cA} = \frac{(27)^{2} }{120}

a_{cA} = 6.075  m/s²

a_{cB} = \frac{(27)^{2} }{120}

a_{cB} = 6.075  m/s²

We replace data in formula (2) to calculate  centripetal  force Fc) :

F_{cA} = m_{A} *a_{cA} = 1100kg*6.075\frac{m}{s^{2} }

F_{cA} = 6682.5 N

F_{cB} = m_{B} *a_{cB} = 1600kg*6.075\frac{m}{s^{2} }

F_{cB} = 9720 N

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4 years ago
The transfer of thermal energy via electromagnetic waves is know as what
katrin2010 [14]

Answer:

Radiation

Explanation:

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3 years ago
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