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MissTica
3 years ago
6

) A 73-mH solenoid inductor is wound on a form that is 0.80 m long and 0.10 m in diameter. A coil having a resistance of is tigh

tly wound around the solenoid at its center. The mutual inductance of the coil and solenoid is At a given instant, the current in the solenoid is and is decreasing at the rate of At the given instant, what is the induced current in the coil
Physics
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Complete question is;. A 73mH solenoid inductor is wound on a form that is 0.80m long and 0.10m in diameter a coil having a resistance of 7.7 ohms is tightly wound around the solenoid at its center the mutual inductance of the coil and solenoid is 19μH at a given instant the current in the solenoid is 820mA and is decreasing at the rate of 2.5A/s at the given instant what is the induced current in the coil

Answer:

6.169 μA

Explanation:

Formula for induced EMF is given by the equation;

EMF = M(di/dt). We are given;

di/dt = 2.5 A/s

M = 19μH = 19 × 10^(-6) H

Thus;

EMF = 19 × 10^(-6) × 2.5.

EMF = 47.5 × 10^(-6) V

Formula for current is;

i = EMF/R. R is resistance given as 7.7 ohms.

Thus; i = 47.5 × 10^(-6)/7.7

i = 6.169 μA

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Answer:

2.877 m/s

Explanation:

According to the laws of conservation of linear momentum,

the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)

Let both players are tackled and moving in V velocity

  • M and m - masses of the players
  • U and  u -  velocities of them respectively (both velocities are towards east direction )

momentum before impact = momentum after impact

                          →MU + →mu  = →(M+ m )v

 91.5  * 2.73 + 63.5 * 3.09 =  (91.5 + 63.5) * V

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A pendulum that moves through its equilibrium position once every 1.000 s is sometimes called a “seconds pendulum.” what is the
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The frequency of the applied RF signal used to excite spins is directly proportional to the magnitude of the static magnetic fie
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The uncertainty in inverse frequency is  \Delta  [\frac{1}{w} ]=  \frac{3}{2000} \ s

Explanation:

From the question we are told that

   The value of the proportionality constant is  k  = 5  \frac{Hz }{T}

   The strength of the magnetic field is  B = 20 \ T

   The change in this strength of magnetic field is  \Delta B = 3  \ T

The magnetic field is given as

           B  =  \frac{k}{\frac{1}{w} }

Where w is frequency

The uncertainty or error of the field is given as

         \Delta  B  =  \frac{k }{[\frac{1}{w}^]^2 }  \Delta [\frac{1}{w} ]

The uncertainty in inverse frequency is given  as

           \Delta  [\frac{1}{w} ]  = \frac{\Delta B}{k [\frac{1}{w^2} ]}

                    \Delta  [\frac{1}{w} ]=  \frac{\Delta B}{k (B)^2 }

substituting values

                  \Delta  [\frac{1}{w} ]=  \frac{3}{5 (20)^2 }

               \Delta  [\frac{1}{w} ]=  \frac{3}{2000} \ s

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