Answer:
the state of giving off light or glow.
Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = ![\omega=7.27\times 10^{-5} rad/s](https://tex.z-dn.net/?f=%5Comega%3D7.27%5Ctimes%2010%5E%7B-5%7D%20rad%2Fs)
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :
![v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s](https://tex.z-dn.net/?f=v%3Dr%5Comega%5C%5C%5C%5Cv%3D%2836000%5Ctimes%2010%5E3%2B6400%5Ctimes%2010%5E3%29%5Ctimes%207.27%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5Cv%3D3082.48%5C%20m%2Fs%5C%5C%5C%5Cv%3D3.08%5C%20km%2Fs)
So, the velocity of the satellite is 3.08 km/s.
Answer:
2.5 m/s²
Explanation:
Using the formula, v = u + at ( v = Final velocity; u = Initial velocity; t = Time; a = Acceleration)
25 = 0 + 10a
a = 25/10 = 2.5 m/s²
I would say your answer is B- Some of the chemical energy from the batteries is converted into heat energy.