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Nezavi [6.7K]
3 years ago
10

2(5m^4n^-1)^3 simplify show work please

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}

Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}

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Sam will spend at most $27 on gifts. So far, he has spent $18. What are the possible additional amounts he will spend? Use c for
Assoli18 [71]

Answer:$9

Step-by-step explanation:

Let the additional amount be c

Total amount to spend on gift is $27

He had spent $18 so far

$18+c= $27

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5 0
3 years ago
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Elena L [17]

It is given that the two figures are similar. This means that mV is equal to mN, mW is equal to mO, and mX is equal to mP. The sum of the angles of a triangle is equal to 180 degrees.

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3 0
3 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti
prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

= \frac{30}{100}

Now write 60% in the decimal form

= \frac{60}{100}

After  drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of  antifreeze is

= \frac{30\times (10 - x)}{100}

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

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solyving

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4 years ago
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Answer:

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Step-by-step explanation:

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