Answer:
74.36 g of aluminium acetate.
730.27g of aluminium acetate.
- to the nearest hundredth.
Step-by-step explanation:
Acetic acid is usually written as CH3COOH.
a. 6CH3COOH + Al(OH)3 ---> Al(CH3COO)3 + 9H2O
So 6 moles of acetic acid produce 1 mole of aluminium acetate.
Using the molecular masses
6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)
348.228 g acetic acid gives 207.142 g Al acetate.
So 125 g gives (207.142 / 348.228) * 125
= 74.36 g of aluminium acetate.
b.
(26.98 + 3*16 + 3 * 1.008) g of Al(OH)3 gives 207.142 g Al acetate
78.004 g gives 207.142 g Al acetate
275 g gives (207.142 / 78.004) * 275
= 730.27g Al acetate.
Answer:
The slope is 4
Step-by-step explanation:
The answer is 4
Answer:
second, third,first
Step-by-step explanation:
first
3/2=1.5
9^1.5=27
second
1/3=0.333
27^0.333=3
third
2/3=0.667
125^0.667=25
Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
Step-by-step explanation:
Because this is a right triangle and it is given that one angle is 45 than also the ather angle is 45 so this triangle has 2 equal sides.So also the ather side is 6 .
Hypotenuse can be found by pythagorean theorem
6^2+6^2=x^2
36+36=x^2
x=√72
