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eduard
1 year ago
6

What is the slope of a line parallel to the line whose equation is 2x + 4y = 56. HELP ASAP

Mathematics
2 answers:
Anton [14]1 year ago
3 0

Answer:

Let's put this equation in standard form...

2x+4y=56\\4y=56-2x\\y=14-0.5x

If it is parallel, it would have the SAME slope but ANY OTHER y-intercept!!

For example...

y=-0.5x+304\\y=-0.5x-67

Hope this helps!!

viktelen [127]1 year ago
3 0

Hi there !

<u>Lets first try to write given line in slope intercept form which is -</u>

❄︎\green{ \underline { \boxed{ \sf{y=mx+c}}}}

Here-

  • m = slope of line
  • c = intercept cut on y- axis

<u>Proceeding</u>-

✰2x + 4y = 56

➪ 4y = -2x +56

➪ y =\dfrac{ -2x +56}{4}

➪ y =\dfrac{ -2x }{4}+  \dfrac{56}{4}

➪ y =\dfrac{ -x }{2}+  14

➪ y =\dfrac{ -1}{2}x +  14

Comparing with slope intercept form -

❄︎\red{ \underline { \boxed{ \sf{m = - \frac{1}{2}}}}}

Now,

✪ Since the parallel lines have same inclination with positive x-axis , their slopes are equal.

❀ So, the slope of a line parallel to the line whose equation is 2x + 4y = 56 would be -\dfrac{1}{2}

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2 years ago
A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo
katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the boxV=x^2z

Volume of the box=12 ft^3\\

Therefore, x^2z=12\\z=\frac{12}{x^2}

The material for the base costs \$0.17/ft^2, the material for the sides costs \$0.10/ft^2, and the material for the top costs \$0.13/ft^2.

Area of the base =x^2

Cost of the Base =\$0.17x^2

Area of the sides =4xz

Cost of the sides==\$0.10(4xz)

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Cost of the Base =\$0.13x^2

Total Cost, C(x,z) =0.17x^2+0.13x^2+0.10(4xz)

Substituting z=\frac{12}{x^2}

C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}

To minimize C(x), we solve for the derivative and obtain its critical point

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Recall: z=\frac{12}{x^2}=\frac{12}{2^2}=3\\

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0
3 years ago
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Kryger [21]

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3 0
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