In order to find zeroes of a function, we will probably want to use our quadratic formula.
-b±√b^2-4(a)(c)/2a
If we know our values, we can plug it in.
Our values:
A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72
Now, We can plug it into our formula.
BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!
-(17)±√(17)^2-4(1)(72)/2(1)
Now we can type it into a calculator!
When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:
-8 & -9.
Here,
cos(x) = sin(35)
cos(x) = cos(90-55)
cos(x) = cos(55)
x = 55
Answer:
well the slope is...
Step-by-step explanation:
4/3 but i don't know about the equation part
Step-by-step explanation: The base of the power in the original equation becomes the base of the log. So we have 
.
Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.
So we have 
which is 3² = 9 written in logarithmic form.
This can also be switched around to read 
.
So the first choice will be your answer.
My work is also show in the image attached,
I just didn't switch it.
