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2 years ago

7

At a food donation drive, the initial ratio of canned drinks to canned food was 3 : 7. The ratio became 5 : 7 after a donation o

f additional 128 canned drinks were made. How many cans of food were there?

2 answers:

xxMikexx [17]2 years ago

8 0

Answer:

the cans of food are 448 in number

cestrela7 [59]2 years ago

3 0

Answer:

448

Step-by-step explanation:

Let's assume the final answer is x

128 ÷ x +3 ÷ 7 = 5 ÷ 7

x = 448

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In a school canteen, a cup of tea costs 60p.

nataly862011 [7]

The expression for the cost function is cost=60y.

We have given that,

a cup of tea costs 60p.

We have to determine the cost function.

<h3>What is the cost function?</h3>

In mathematical optimization and decision theory, a loss function or cost function is a function that maps an event or values of one or more variables onto a real number intuitively representing some cost associated with the event. An optimization problem seeks to minimize a loss function.

Cost=no of cups(price for one cup)

cost=60y

Therefore the expression for the cost function is cost=60y.

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3 years ago

What decimal is 1/10 of 0.08

Oksana_A [137]

1/10 * 0.08 = 0.08 * 0.1 = 0.008

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3 years ago

Dima020 [189]

Answer: I can help you to solve by graphing the second one, the 2 answers are 1. Slope: 1/3, x-intercept: (–6, 0), and y-intercept: (0, 2). And 2. X-intercept: (–3, –2, –5/6, 0, 1) and Y-intercept: (–16, –6, –23/12, –4, –12)

Step-by-step explanation:

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3 years ago

If P(A)=.55, P(B)=.32 And P(AuB)=.70,

son4ous [18]

Answer:

A. 0.5313

B. 0.15

Step-by-step explanation:

Given:

$P(A)=0.55\\ \\P(B)=0.32\\ \\P(A\cup B)=0.70$

First , use formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

to find $P(A\cap B):$

$0.70=0.55+0.32-P(A\cap B)\\ \\P(A\cap B)=0.55+0.32-0.70=0.87-0.70=0.17$

A. Use formula

$P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\ \\P(A|B)=\dfrac{0.17}{0.32}=\dfrac{17}{32}=0.53125\approx 0.5313$

B. Use formula

$P(A'|B)=P(B)-P(A\cap B)=0.32-0.17=0.15$

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3 years ago

Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge

nekit [7.7K]

In the elimination method one variable is eliminated from the system of equation to find the value of other.

The first equation must be multiplied by 18 and second equation must be multiplied by 8.

<h3>What is elimination method?</h3>

To solve the system of equation and find the value of the variables, the elimination method is used.

In this method one variable is eliminated from the system of equation to find the value of other.

Given information-

The system of equation given in the problem is,

$\dfrac{1}{4}x -\dfrac{1}{6}y =5\\$ ......1

Let the above equation as equation 1.

The second equation given in the problem is,

$\dfrac{4}{5}x +\dfrac{3}{8}y =10$ ......2

Let the above equation as equation 2.

To eliminate the y term, make the coefficient of <em>y</em> of both the equation equal.

As the coefficient of <em>y</em> of the equation 2 is 3/8. Thus multiply second equation with 8 to eliminate coefficient. Thus,

$8\times \dfrac{4}{5}x +8\times\dfrac{3}{8}y =8\times10\\$

$\dfrac{32}{5}x +3y =80$ .....3

Multiply equation 1 with 18 to make the coefficient of y equal. Thus,

$18 \times\dfrac{1}{4}x -18\times\dfrac{1}{6} \times y =18 \times5$

$\dfrac{18}{4}x -3 =90$ ......4

Add equation 3 and equation 4 as,

$\dfrac{32}{5}x +3y+ \dfrac{18}{4}x -3y =80+90$

$\dfrac{32}{5}x + \dfrac{18}{4}x =170$

Hence the first equation must be multiplied by 18 and second equation must be multiplied by 8.

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3 years ago

Read 2 more answers