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pickupchik [31]

2 years ago

13

HELP HE:LP HELPPPPPPPPPPp

2 answers:

kozerog [31]2 years ago

8 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(

8

,

−

2

)

Equation Form:

x

=

8

,

y

=

−

2

krek1111 [17]2 years ago

8 0

Step-by-step explanation below:

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What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1

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A horizontal asymptote of a function f(x) is given by y = lim f(x) as x --> ∞ and x --> –∞. In this case,
$\lim_{x \to \infty} \frac{-2x}{x+1} = \lim_{x \to \infty} \frac{-2x}{x(1+ \frac{1}{x} )}\\
=\lim_{x \to \infty} \frac{-2}{1+ \frac{1}{x} }\\
= -2
$

Thus, the horizontal asymptote of f(x) is y = –2.

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Step-by-step explanation:

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Step-by-step explanation:

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One factor of the function f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5) Describe how to find the x-intercepts and the y-intercept o

pickupchik [31]

Answer:

x-intercept(s): (−1.9900717, 0)

y-intercept(s): (0, 52.5)

Step-by-step explanation:

To find the x-intercept, substitute in $0$ for $y$ and solve for $x$ . To find the y-intercept, substitute in $0$ for $x$ and solve for $y$ .

$f(x)=y$

$(x)=x$

<u>x-intercept</u>

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=\bold{0}=x^3-8x^2+17x-10.5\left(x-5\right)$

$=0\cdot \:10=x^3\cdot \:10-8x^2\cdot \:10+17x\cdot \:10-10.5\left(x-5\right)\cdot \:10$

$=0=10x^3-80x^2+170x-105\left(x-5\right)$

$=0=10x^3-80x^2+65x+525$

$=10x^3-80x^2+65x+525=0$

$=10x^2-99.90071\dots x+263.80959\dots \approx \:0$

$\bold{x\approx \:-1.99007\dots}$

<u>y-intercept</u>

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=y=\bold{0}^3-8(\bold{0})^2+17(\bold{0})-10.5\left(\bold{0}-5\right)$

$=y=0-8\cdot \:0+17\left(0\right)-10.5\left(0-5\right)$

$=y=0-8\cdot \:0+17\cdot \:0-10.5\left(0-5\right)$

$=y=0-0+0-\left(-52.5\right)$

$=0-0+0+52.5$

$\bold{y=52.5}$

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