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pickupchik [31]
2 years ago
13

HELP HE:LP HELPPPPPPPPPPp

Mathematics
2 answers:
kozerog [31]2 years ago
8 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(

8

,

−

2

)

Equation Form:

x

=

8

,

y

=

−

2

krek1111 [17]2 years ago
8 0
Step-by-step explanation below:

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Heather counted the number of crickets in her greenhouse every month and recorded the data in the table below.
skelet666 [1.2K]

Answer: Its B

Step-by-step explanation:

I did this test and got it right

7 0
3 years ago
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Add the multiple fractions then simplify the answer.
bekas [8.4K]
Find the LCM between the denominators.

The LCM is 36

Divide he LCM for the denominators, then multiply the result for the numerator.

\frac{12+9+4}{36}

You get 25/36 and you can't simplify it
4 0
3 years ago
The temperature falls from 3°C to -4°C. What is the difference in these temperatures?
raketka [301]

Answer:

-1

Step-by-step explanation:

3- 4 = -1

3 0
4 years ago
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What is the answer to number 3??
Eduardwww [97]

The change in temperature has dipped from -2 degrees Celsius to -10 degrees Celsius, meaning there is a negative diversification.

-10 degrees Celsius is equal to 14 degrees Fahrenheit.

-2 degrees Celsius is equal to 28.40 degrees Fahrenheit.

Thus, the temperature gap is 14.40 degrees Fahrenheit.

8 0
4 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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