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3 years ago

11

Alana organized some resources in a table. which best describes alana’s error? geothermal energy is not found underground. petro

leum is limited in supply. sunlight cannot be used to generate electricity. coal is not considered a fossil fuel.

1 answer:

Akimi4 [234]3 years ago

4 0

Which energy is best discribed for you and math

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a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 91.5 kg$ is the mass of the first player

$u_1 = 3.73 m/s$ is the initial velocity of the first player (we take east as positive direction)

$m_2 = 63.5 kg$ is the mass of the second player

$u_2 = 3.09 m/s$ is the initial velocity of the second player

$v$ is their final combined velocity after the collision

Re-arranging the equation and substituting the values, we find:

$v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(3.73)+(63.5)(3.09)}{91.5+63.5}=3.47 m/s$

So, their velocity afterwards is 3.47 m/s east.

Learn more about momentum:

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6 0

3 years ago

A train departs from its station at a constant acceleration of 5m/s2. What is the speed of the train at the end of 20 seconds

Shalnov [3]

a = v/t

v = a.t

v = 5 * 20 = 100m/s

8 0

4 years ago

How is this career a good fit for you or an individual who would work in this field

kiruha [24]

Answer:

Which career is it?

4 0

4 years ago

A gas cylinder holds 0.10 mol of O2 at 150 C and a pressure of 3.0 atm. The gas expands adiabatically until the pressure is halv

yKpoI14uk [10]

Answer:

V2 = 1.899*10^-3 m^3

T2 = 347.125 K

Explanation:

Using gas law, we know that

PV = nRT,

Where

V1 = 0.00115743 m^3.

gamma = 1.4

Now, when we solve for final volume, V2 we get

V2 = V1/((P2/P1)^(1/gamma))

V2 = 1.899*10^-3 m^3

Using the same law and method, when we try to solve for the temperature, we find that the final temperature, T2 is

T2 = T1*((V1/V2)^(gamma-1))

T2 = 347.125 K

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3 years ago

Shelly was surprised to learn the dwarf planet Pluto used to be considered a planet. What would have had to be true for Pluto to

tekilochka [14]

The second answer is the correct response, as Pluto is found in the kuiper belt, and there are objects that are roughly the same size as Pluto.

7 0

4 years ago

Read 2 more answers