Answer:
a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)
b) The acceleration of point A is 3.25 m/s²
The acceleration of point E is 0.75 m/s²
Explanation:
a) The relative acceleration of B with respect to D is equal:

Where
aB = absolute acceleration of point B = 2.5 j (m/s²)
aD = absolute acceleration of point D = 1.5 j (m/s²)
(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam
(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)


We have that
(aB/D)t = BDα
Where α = acceleration of the beam
BDα = 1 m/s²
Where
BD = 2

b) The acceleration of point A is:

(aA/D)t = ADαj

The acceleration of point E is:
(aE/D)t = -EDαj

Answer:
Pressure,
Explanation:
It is given that,
Mass of the woman, m = 55 kg
Diameter of the circular cross section, d = 6 mm
Radius, r = 3 mm = 0.003 m
Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :




So, the pressure exerted on the floor is
. Hence, this is the required solution.
Answer:
Explanation:
From the given information:
Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

Given that;
m_1 = 1 and
m_2 = 4
Therefore,


Making
the subject of the formula:

=15.84
≅ 16
Hence, we can conclude that star X is more luminous by a factor of 16