Answer:
488.6KN
Explanation:
Hello!
the first step to solve this problem we must find the pressure exerted at the bottom of the tank (P) which is the sum of the external air pressure (P1 = 92kPa), the pressure inside the tank (P2 = 100kPa) and the pressure due to the weight of the water (P3), taking into account the above we have the following equation
P=P1+P2+P3
to find the pressure at the bottom of the tank due to the weight of the water we use the following equation
where
α=density=1 g/cm^3=1000kg/M^3
H=height=14.1m
g=gravity=3.71m/s^2
solving
P3=(1000)(14.1)(3.71)=52311Pa=52.3kPa
P=P1+P2+P3
P=100kPa+92kPa+52.3kPa=244.3kPa
finally to solve the problem we remember that the pressure is the force exerted on the area