All categories

3 years ago

The surface area of a postage

Physics

2 answers:

balu736 [363]3 years ago

8 0

Answer:

608

Explanation:

I only answer after making sure the answer is correct and I get the green tick, not the red cross (Acellus)

ANTONII [103]3 years ago

4 0

Answer:

608

Explanation:

Trust me

You might be interested in

Scientists around the world have been working for decades on perfecting the process of

vlada-n [284]

Answer:

Scientists are looking for a way to create cheap, safe, and sustainable energy.

Nuclear fusion is the process by which two atoms rapidly collide at each other forming a new nucleus. The energy of colliding and synthesizing has intrigued scientist into believing that this could be one of best sources of renewable energy.Explanation:

3 0

3 years ago

After pulling the string tight, Miguel talked into his aluminum can. Brian could hear Miguel's voice through the aluminum can at

Alex73 [517]

Answer:

option C is correct✅✅✅✅✅

...............

8 0

3 years ago

How long will the energy in a 1470-kJ (350-kcal) cup of yogurt last in a woman doing work at the rate of 150 W with an efficienc

Lyrx [107]

Answer:

The 1470 kJ of energy supplied by the yogurt would be consumed by 150 W of work (efficiency of 20%) in about 32.7 h. Then if people is not careful, easily would have more energy from the food that the amount that can consume exercising.

Explanation:

Step 1.

Energy supplied: 1470 kJ = 1470000 J.

Rate of energy used for the : 150 W = 150 J/s. <em>This means that each second of this kind of work requieres 150 J of energy,</em>

Step 2

For this case, efficiency is defined as the relationship between the actual rate of energy used, to the rate of energy consumed to obtain it. So:

$Eficiency=\frac{E_{obtain} }{E_{consumed} } \\$

Then the rate of energy required for this work, is calculated solving for $E_{Consumed}$ :

$E_{consumed} =\frac{E_{obtain}}{Efficiency} =\frac{150\frac{J}{s} }{0.20} =750\frac{J}{s}$

<em>This means that for a work that as a rate of 150 J/s , It requieres to consume energy at a rate of 750 J/s.</em>

Step 3

Now, it is possible to calculate how much time would be needed to consume the 1470000 J of energy of the yogurt. It done using this relationship:

$Time=\frac{Energy}{rate}$

Where Energy stands for the total amount of energy that would be consumed, and rate stans for the rate of energy consumption, Then the time would be:

$Time=\frac{1470000J}{750\frac{J}{s} }=1960s=32.7 h$

Then if for the consumption of 1470 kJ of energy is required almost 33 hours, Then is easy to see that the amount of enegy that can be obtain of food would much more than the amount that can be depleted by exercise

5 0

3 years ago

A car moving at 95 km/h passes a 1.00-km-long train traveling in the same direction on a track that isparallel to the road. If t

victus00 [196]

Answer:

Time to pass the train=0.05 h

How far the car traveled in this time=4.75 Km

Explanation:

We have that the train and the car are moving in the same direction, the difference between the speed of the vehicles is:

$\Delta V=V_{car}-V_{train}=95km/h-75km/h=20km/h$

We will use this difference in the speed of the car an train to calculate how much time take the car to pass the train. For this we have that the train is 1km long and the car is moving with a speed of 20km/h (we use this value because is the speed that the car have in advantage of the train) then for a movement with a constant speed we have:

$V=\dfrac{x}{t}$

Where x is the distance, t is the time and v is the speed. using the data that we have:

$V=\dfrac{x}{t}=\dfrac{1km}{20km/h}=0.05h$

This is the time that the car take to pass the train. Now to calculate how far the car have traveled in this time we have to considered the speed of 95Km/h of the car, then:

$V=\dfrac{x}{t}\\x=v\cdot t\\x=95km/h\cdot 0.05h\\x=4.75km$