8^2=8x8=16 then you add 4 and subtract 12 which will get you 56. correct me if i’m wrong.
The total area under the curve must equal 1. Let the value of the density curve be x. Then 10x = 1. Therefore x = 1/10 or 0.1.
The correct answer is D. 0.1.
3f + 2g = 30 . . .(1)
f + 2g = 26 . . . .(2)
(1) - (2) => 2f = 4 => f = 4/2 = 2
From (2), 2 + 2g = 26 => 2g = 26 - 2 = 24 => g = 24/2 = 12
Therefore, f = 2 and g = 12
I know that you should use PEMDAS, what grade are you in this sems advances for you
