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2 years ago

A packet of vegetable seeds has a germination rate of

Mathematics

1 answer:

Doss [256]2 years ago

8 0

N = number of seeds planted

P = probability of germination

K = number that germinated

Using probability calculation:
p(x = k) = (n k) x 0.90^K x 0.10^n-k

p(10) = (12 10) x 0.90^10 x 0.10^2

P(10) = 0.2310

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Consider the point (x,y) lying on the graph of the line 6x + 4y = 7. Let L be the distance from the point (x,y) to the origin

alukav5142 [94]

Try this solution, note, the shown way is not the shortest one.

The answer is marked with red colour.

5 0

3 years ago

What addition sentence does this show?

goldfiish [28.3K]

The answer is C because when adding two negatives it equals a positive

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3 years ago

Angle 1 and Angle 2 are supplementary. Angle 1 is 20 degree less than nine times the size of angle 2.

nadya68 [22]

Answer:

∠1=160° and ∠2=20°

Step-by-step explanation:

Let ∠1 = x

∠2 = y

as these two angles are supplementary their sum is 180

that x+y=180 ----(A)

Also given that ∠1 is 20 degree less than nine times the size of ∠2.

Hence

x=9y-20

putting value of x in A and solving for y

9y-20+y=180

10y=180+20

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Putting this y in A

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5 0

3 years ago

One sample has Aa Aa One sample has n 10 scores and a variance of s2 20, and a second sample has n 15 scores and a variance of s

siniylev [52]

Answer:

option (a) It will be closer to 30 than to 20

Step-by-step explanation:

Data provided in the question:

For sample 1:

n₁ = 10

variance, s₁² = 20

For sample 2:

n₂ = 15

variance, s₂² = 30

Now,

The pooled variance is calculated using the formula,

$S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}$

on substituting the given respective values, we get

$S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}$

$S^{2}_{p}$ = 26.0869

Hence,

the pooled variance will be closer to 30 than to 20

Therefore,

The correct answer is option (a) It will be closer to 30 than to 20

4 0

3 years ago

hat is the approximate distance between Portland, Oregon (45° north, 122° west), and San Francisco, California (37° north, 122°

juin [17]

<span>Since both places are on the same longitude (122° west) and different lattitudes 45° north and 37° north, the distance between the two place lies on a great circle (along a line of longitude). Difference in latitudes = 45 - 37 = 8° (subtract the lattitudes because both sides are on the same side in the latitude i.e. both are north) The distance between two points along the line of longitude is given by theta / 360 x 2 x pi x R: where theta = 8° and R is the radius of the earth = 3,960 miles. d = 8 / 360 x 2 x pi x 3960 = 552.9 miles</span>

8 0

3 years ago