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dimaraw [331]
2 years ago
12

Compare the backpack weights for the students in the three classes.

Mathematics
1 answer:
Lina20 [59]2 years ago
5 0
Seventh graders backpacks weigh less than Eleventh graders back packs
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Please help me with precal
Doss [256]

Consider the function f(x)=\sqrt{x}. This function has:

  • the domain x\in [0,\infty);
  • the range y\in [0,\infty).

If the domain of unknown function is [a,\infty), then x\ge a or x-a\ge 0. This means that you have \sqrt{x-a} as a part of needed function.

If the range of unknown function is [b,\infty), then y\ge b. This means that you have to translate function b units up and then the expression of the function is

y=\sqrt{x-a}+b.

Answer: correct choice is B.

6 0
3 years ago
Jared surf for one third of the nine hours he was at the beach he spent the rest of the time building a sandcastle how many hour
WINSTONCH [101]
9 dived by 3 = 3
so he surfed for 3 hours = 1/3 of 9
and there are 6 hours left 

so he spent 6 hours building a sandcastle 
8 0
3 years ago
Read 2 more answers
It costs luis 5$ to park his car at a parking meter for 2 hours. What is the price to park for 1 hour? Draw a bar model or write
Aliun [14]

Answer:

$2.50

Step-by-step explanation:

If it costs $5 for two hours and one hour is half of two hours, you take half of $5 and use it as your answer, so your answer is $2.50

3 0
3 years ago
Find the volume of a cylinder with a diameter of 10 inches and a height of 20 inches. Use 3.14 for π.
Snowcat [4.5K]
<span>Lets find the volume of a cylinder with a diameter D=10 inches and lenght L= 20 inches. First we need to notice that the diameter is twice the size of the radius: D=2r. Then we write the equation for the volume of the cylinder. it is the base times the height: V=pi*r^2 * L. Now we input the nubmers in the equation: V=3.14*(D/2)^2 * L where r=D/2=5 inches and after calculating we get: V=1570 inches^3</span>
6 0
3 years ago
Read 2 more answers
Math help @LIEMONDER
klio [65]
First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)
5 0
3 years ago
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