Which of these following equations solve for x in the two pictures
1 answer:
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Answer:
The data is skewed to the bottom and contains an outlier.
Step-by-step explanation:
1. Test for outlier
An outlier is a point that is more than 1.5IQR below Q1 or above Q3.
IQR = Q3 - Q1 = 74 - 51 = 23
1.5 IQR = 1.5 × 23 = 34.5
51 - 15 = 36 > 1.5IQR
The point at 15 is an outlier.
2. Test for normal distribution
The median is not in the middle of the box.
Rather, it cuts the box into two unequal parts, so the data does not have a normal distribution.
3. Test for skewness
The longer part is to the left of the median, so the data is skewed left.
<u>Answer:</u>
The denominator of a fraction is 4 more than the numerator. The original fraction is
<u>Solution:</u>
Given that
Denominator of fraction is 4 more than the numerator.
Let’s say numerator of fraction be represented by variable x.
So denominator of a faction as it is four more that numerator will be x + 4
Also given if both decreased by three than simplified result is
Solving above equation for x
=> 7(x – 3 ) = 6 ( x + 1 )
=> 7x – 21 = 6x + 6
=> 7x – 6x = 6 + 21
=> x = 27
Numerator of fraction = x = 27
Denominator of fraction = x + 4 = 27 + 4 = 31
Hence the original fraction is