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igor_vitrenko [27]
3 years ago
7

Distance between (5,8) (-1,-4)? ​

Mathematics
2 answers:
umka2103 [35]3 years ago
3 0

Answer:

The distance between (5,8), and (-1,4) is (6, 12).

Step-by-step explanation:

All you have to do is think of it as a line. -1 is here, to get to positive 5, you must move 6; -4 is there, to get to positive 8, you must move 12.

Oduvanchick [21]3 years ago
3 0

Answer:

\huge\boxed{\sqrt{180} \ \ \text{or}  \ \ 13.42}

Step-by-step explanation:

In order to find the distance between two points, we can use the distance formula. The distance formula states that the distance between two points is

\sqrt{(x_2 - x_1)^2 + (y_2 - y_1) ^2}

(5,8) is our first coordinate and (-1,-4) is our second. So, we can substitute these values into the equation.

\sqrt{(-1 - 5)^2 + (-4 - 8) ^2}\\\\\sqrt{(-6)^2 + (-12) ^2}\\\\\sqrt{36 + 144}\\\\\sqrt{180} \approx 13.42

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It takes 10.155 years until you have $3,000 ⇒ 3rd

Step-by-step explanation:

The formula for compound interest, including principal sum is:

A=P(1+\frac{r}{n})^{nt} , where

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  • P is the principal investment amount  
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
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∵ You decide to put $2,000 in a savings account

∴ P = 2000

∵ You want to save for $3,000

∴ A = 3000

∵ The account has an interest rate of 4% per year and is

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- Substitute all of these values in the formula above to find t

∵ 3000=2000(1+\frac{0.04}{12})^{12t}

- Divide both sides by 2000

∴ 1.5=(1+\frac{1}{300})^{12t}

∴ 1.5=(1\frac{1}{300})^{12t}

- Change the mixed number to an improper fraction

∴ (1.5)=(\frac{301}{300})^{12t}

- Insert ㏒ for both sides

∴ log(1.5)=log(\frac{301}{300})^{12t}

- Remember log(a)^{n}=nlog(a)

∴ log(1.5)=(12t)log(\frac{301}{300})

- Divide both sides by log(\frac{301}{300})

∴ 121.84 = 12 t

- Divide both sides by 12

∴ 10.155 = t

It takes 10.155 years until you have $3,000

Learn more:

You can learn more about the compound interest in brainly.com/question/4361464

#LearnwithBrainly

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