Answer:
The correct answer is: 
Step-by-step explanation:
You're using Acellus, right?
Let me guess: Algebra I?
Well the volume of the cylinder will be equal area of base time height
V = pi(4)^2 *(12)
The formula for the volume of a sphere is V = 4/3 πr³.
9514 1404 393
Answer:
{4, 5, 6, 7, 8}
Step-by-step explanation:
The inequality related to the perimeter is ...
x +(x +4) +11 < 32
2x < 17 . . . . . . . . . . . . subtract 15
x < 8.5
The inequality related to the triangle inequality is ...
(x) +(x +4) > 11
2x > 7
x > 3.5
Then possible whole-number values of x are ...
{4, 5, 6, 7, 8}
The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
Rewrite <span>2cos x + 1 = 0 as:
2 cos x = -1, and then cos x = -1/2
x must be in Quadrant II or Quadrant III, since the adj. side is negative.
Note that the angle 120 has adj. side -1 and hyp 2. So 120 degrees is one solution.
Now what about a possible 2nd solution, to be found in Quadrant III? That would be -120 degrees, which has the same terminal line as does 240 degrees.
No soap.
So, the solution is 120 degrees.</span>
